32位有upx壳
脱壳
该函数通过对输入的处理来当byte_4021A0数组的下标，再通过对v8进行处理得到v11和v12的值，再通过这个(v11 + v12) ^ 0x19判断byte_4021A0数组的下标对应的元素是否与其相等，若相等则返回1，输出正确
获取加密的数组，编写逆向脚本
使用正向爆破的方法，通过测试ascii32-127的范围来爆破如果正确则保留正确的值
list1=[50, 97, 52, 57, 102, 54, 57, 99, 51, 56, 51, 57, 53, 99, 100, 101, 57, 54, 100, 54, 100, 101, 57, 54, 100, 54, 102, 52, 101, 48, 50, 53, 52, 56, 52, 57, 53, 52, 100, 54, 49, 57, 53, 52, 52, 56, 100, 101, 102, 54, 101, 50, 100, 97, 100, 54, 55, 55, 56, 54, 101, 50, 49, 100, 53, 97, 100, 97, 101, 54]
list2=[97, 52, 57, 102, 54, 57, 99, 51, 56, 51, 57, 53, 99, 100, 101, 57, 54, 100, 54, 100, 101, 57, 54, 100, 54, 102, 52, 101, 48, 50, 53, 52, 56, 52, 57, 53, 52, 100, 54, 49, 57, 53, 52, 52, 56, 100, 101, 102, 54, 101, 50, 100, 97, 100, 54, 55, 55, 56, 54, 101, 50, 49, 100, 53, 97, 100, 97, 101, 54]
list3=[99, 124, 119, 123, 242, 107, 111, 197, 48, 1, 103, 43, 254, 215, 171, 118, 202, 130, 201, 125, 250, 89, 71, 240, 173, 212, 162, 175, 156, 164, 114, 192, 183, 253, 147, 38, 54, 63, 247, 204, 52, 165, 229, 241, 113, 216, 49, 21, 4, 199, 35, 195, 24, 150, 5, 154, 7, 18, 128, 226, 235, 39, 178, 117, 9, 131, 44, 26, 27, 110, 90, 160, 82, 59, 214, 179, 41, 227, 47, 132, 83, 209, 0, 237, 32, 252, 177, 91, 106, 203, 190, 57, 74, 76, 88, 207, 208, 239, 170, 251, 67, 77, 51, 133, 69, 249, 2, 127, 80, 60, 159, 168, 81, 163, 64, 143, 146, 157, 56, 245, 188, 182, 218, 33, 16, 255, 243, 210, 205, 12, 19, 236, 95, 151, 68, 23, 196, 167, 126, 61, 100, 93, 25, 115, 96, 129, 79, 220, 34, 42, 144, 136, 70, 238, 184, 20, 222, 94, 11, 219, 224, 50, 58, 10, 73, 6, 36, 92, 194, 211, 172, 98, 145, 149, 228, 121, 231, 200, 55, 109, 141, 213, 78, 169, 108, 86, 244, 234, 101, 122, 174, 8, 186, 120, 37, 46, 28, 166, 180, 198, 232, 221, 116, 31, 75, 189, 139, 138, 112, 62, 181, 102, 72, 3, 246, 14, 97, 53, 87, 185, 134, 193, 29, 158, 225, 248, 152, 17, 105, 217, 142, 148, 155, 30, 135, 233, 206, 85, 40, 223, 140, 161, 137, 13, 191, 230, 66, 104, 65, 153, 45, 15, 176, 84, 187, 22, 72, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
v4=0
flag=''
for i in range(35):
v8 = list1[2 * i]
if v8 < 48 or v8 > 57:
v9 = v8 – 87
else:
v9 = v8 – 48
v10 = list2[2 * i]
v11 = 16 * v9
if v10 < 48 or v10 > 57:
v12 = v10 – 87
else:
v12 = v10 – 48
v4=(v11 + v12) ^ 25
flag+=chr(list3.index(v4))
print(flag)
